Show that ((7+3sqrt5)/(sqrt2+sqrt7+3sqrt5)+((7-3sqrt5)/(sqrt2+sqrt7-3sqrt5))=2sqrt2
Perhaps, condition is incorrect:
(7+35)(2+7+35)+(7−35)(2+7−35)=22\dfrac{(7+3\sqrt5)}{(\sqrt2+\sqrt7+3\sqrt5)}+\dfrac{(7-3\sqrt5)}{(\sqrt2+\sqrt7-3\sqrt5)}=2\sqrt2(2+7+35)(7+35)+(2+7−35)(7−35)=22
(7+35)(2+7+35)+(7−35)(2+7−35)≈\dfrac{(7+3\sqrt5)}{(\sqrt2+\sqrt7+3\sqrt5)}+\dfrac{(7-3\sqrt5)}{(\sqrt2+\sqrt7-3\sqrt5)}\approx(2+7+35)(7+35)+(2+7−35)(7−35)≈ 1.1628452441.1628452441.162845244
22≈2\sqrt2\approx22≈ 2.8284271242.8284271242.828427124
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