Question #172366

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Find the inverse for y=(x-3)3+1


Expert's answer

y=(x3)3+1y=(x-3)^3+1

Interchange the variables:

x=(y3)3+1x=(y-3)^3+1

Solve for yy :

x=(y3)3+1x=(y-3)^3+1

(y3)3=x+1-(y-3)^3=-x+1

(y3)3=x1(y-3)^3=x-1

y3=x13y-3=\sqrt[3]{x-1}

y=x13+3y=\sqrt[3]{x-1}+3

Replace the yy with f1(x)f^{-1}(x) to show the final answer:

f1(x)=x13+3f^{-1}(x)=\sqrt[3]{x-1}+3



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