Answer to Question #172365 in Algebra for william

Question

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Find the inverse for y= 2x²-8

Answer 1

$y = 2x^2 - 8$

$y + 8 = 2x^2$

$x^2 = {y+8 \above{1pt} 2}$

$x = \sqrt{\smash[b]{y+8 \above{1pt} 2}}$