Question #172364

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Solve for the inverse y= square root of x-2+4

1
Expert's answer
2021-03-30T13:44:44-0400

Given the function


y=x2+4y =\sqrt{x-2}+4\\


Let


y=f(x)y=f(x)

f(x)=x2+4\therefore f(x) =\sqrt{x-2}+4\\

We want to find f1(x)f^{-1}(x)

y=x2+4y4=x2y =\sqrt{x-2}+4\\ y-4 =\sqrt{x-2}\\

Squaring both sides


(y4)2=(x2)2(y4)2=x2(y4)2+2=x(y-4)^2 =(\sqrt{x-2})^2\\ (y-4)^2 = x-2\\ (y-4)^2+2 = x

Therefore, the inverse of the function is


f1(x)=(x4)2+2f^{-1}(x) = (x-4)^2+2


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