Question #172364

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Solve for the inverse y= square root of x-2+4

Expert's answer

Given the function


y=x−2+4y =\sqrt{x-2}+4\\


Let


y=f(x)y=f(x)

∴f(x)=x−2+4\therefore f(x) =\sqrt{x-2}+4\\

We want to find f−1(x)f^{-1}(x)

y=x−2+4y−4=x−2y =\sqrt{x-2}+4\\ y-4 =\sqrt{x-2}\\

Squaring both sides


(y−4)2=(x−2)2(y−4)2=x−2(y−4)2+2=x(y-4)^2 =(\sqrt{x-2})^2\\ (y-4)^2 = x-2\\ (y-4)^2+2 = x

Therefore, the inverse of the function is


f−1(x)=(x−4)2+2f^{-1}(x) = (x-4)^2+2


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