Determine the x-intercepts of a cubic function y= x2 - 2x2- 5x + 6
y = x³ - 2x² - 5x + 6
"y = 1\u00b2 - 2(1)\u00b2 - 5(1) + 6\\\\\n\ny = 1 -2 -5 +6\\\\\n\ny = 0\\\\"
"\\therefore" x= 1 is an intercept on the x axis
"\\dfrac{x\u00b3 - 2x\u00b2 - 5x + 6}{x-1 } = x\u00b2 - x - 6"
"x\u00b2 - x - 6 = (x -3)(x+2)"
"\\therefore" the x - intercepts of the cubic function are -2, 1 and 3
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