Determine the x-intercepts of a cubic function y= x2 - 2x2- 5x + 6
y = x³ - 2x² - 5x + 6
y=1²−2(1)²−5(1)+6y=1−2−5+6y=0y = 1² - 2(1)² - 5(1) + 6\\ y = 1 -2 -5 +6\\ y = 0\\y=1²−2(1)²−5(1)+6y=1−2−5+6y=0
∴\therefore∴ x= 1 is an intercept on the x axis
x³−2x²−5x+6x−1=x²−x−6\dfrac{x³ - 2x² - 5x + 6}{x-1 } = x² - x - 6x−1x³−2x²−5x+6=x²−x−6
x²−x−6=(x−3)(x+2)x² - x - 6 = (x -3)(x+2)x²−x−6=(x−3)(x+2)
∴\therefore∴ the x - intercepts of the cubic function are -2, 1 and 3
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