Answer to Question #171671 in Algebra for Moel Tariburu

Question #171671

Determine the x-intercepts of a cubic function y= x2 - 2x2- 5x + 6


1
Expert's answer
2021-03-16T08:40:58-0400

y = x³ - 2x² - 5x + 6


y=1²2(1)²5(1)+6y=125+6y=0y = 1² - 2(1)² - 5(1) + 6\\ y = 1 -2 -5 +6\\ y = 0\\


\therefore x= 1 is an intercept on the x axis


x³2x²5x+6x1=x²x6\dfrac{x³ - 2x² - 5x + 6}{x-1 } = x² - x - 6


x²x6=(x3)(x+2)x² - x - 6 = (x -3)(x+2)


\therefore the x - intercepts of the cubic function are -2, 1 and 3


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