Find two consecutive even integers such that the smaller added to three times the larger gives a sum of 38.
Let x represent the smaller integer and y the bigger integer. Since they are consecutive even integers, we have that
"y= x +2"
Also, interpreting the given data, we have that
"x +3y = 38\\\\ x +3(x+2) = 38\\\\ x + 3x + 6 = 38\\\\ 4x + 6 = 38\\\\ 4x = 32 \\\\ x = 8 \\\\ \\therefore y = 10"
So the two consecutive even integers are 8 and 10.
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