Solve the equation: (3x-4)1/2=2
(3x−4)12=2⇒{3x−4>03x−4=22⇒{x>433x=4+4⇒{x>43x=83⇒x=83{(3x - 4)^{\frac{1}{2}}} = 2 \Rightarrow \left\{ {\begin{matrix} {3x - 4 > 0}\\ {3x - 4 = {2^2}} \end{matrix}} \right. \Rightarrow \left\{ {\begin{matrix} {x > \frac{4}{3}}\\ {3x = 4 + 4} \end{matrix}} \right. \Rightarrow \left\{ {\begin{matrix} {x > \frac{4}{3}}\\ {x = \frac{8}{3}} \end{matrix}} \right. \Rightarrow x = \frac{8}{3}(3x−4)21=2⇒{3x−4>03x−4=22⇒{x>343x=4+4⇒{x>34x=38⇒x=38
Answer: x=83x = \frac{8}{3}x=38
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