Question #169128

Solve the equation: 3sqaure root -3x+4=2

1
Expert's answer
2021-03-09T12:35:51-0500

Solution.3x+43=2;3x+4>0;3x>4;(1)3x<4;x<4/3.3x+43=2;33x+4=8;3x=4;x=4/3.Answer:x=4/3.Solution. \newline \sqrt[3]{-3x+4}=2; \newline -3x+4>0; \newline -3x>-4; |*(-1) \newline 3x<4; \newline x<4/3. \newline \sqrt[3]{-3x+4}=2; |^3 \newline -3x+4=8; \newline -3x=4; \newline x=-4/3. \newline Answer: x=-4/3.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS