Answer to Question #169015 in Algebra for khloe

Question #169015

find the equation of a line that has a gradient of 3 and poassess through the point A(1,7)


1
Expert's answer
2021-03-07T10:12:27-0500

y=kx+by = kx + b is an equation of a line, where kk is the slope (or gradient) and bb is the yy -intercept;

k=3k = 3 by condition \Rightarrow y=3x+by = 3x + b .

Since the line passes through the point A(1,7)A (1,7) , then we substitute the coordinates of the point into the equation: 7=31+bb=73=47 = 3 \cdot 1 + b \Rightarrow b = 7-3 =4 \Rightarrow The equation of a line is y=3x+4y = 3x + 4 .




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