Answer to Question #168105 in Algebra for Kimberli

Question

Given the function below, algebraically solve the following system of equation. Please show all work.

y= x^2+2x+3

2y-2x=10

Answer 1

2*y-2*x=10 is the same that y - x = 5 $\implies$ y = x + 5. Substitute this to first expression:

y = x²+2x+3 $\implies$ x + 5 = x²+2x+3 $\implies$ x²+ x - 2 = 0 $\implies$ x₁ = 1 , x₂ = -2. Hence y₁ = 6, y₂ = 3.