Question #166961

In Desmos, type in both equations:

  1. y= square root of x
  2. y= square root x-3+4

What transformations occurred in the graph?


1
Expert's answer
2021-03-17T07:07:11-0400
y=5x+13y=5\sqrt[3]{x+1}

Parent function f(x)=x3.f(x)=\sqrt[3]{x}.

To graph g(x)=x+13,g(x)=\sqrt[3]{x+1}, we shift the graph of ff to the left 1 unit.

To graph h(x)=5x+13,h(x)=5\sqrt[3]{x+1}, stretch the graph of gg vertically by a factor of 5.5.Function is given as:

y=x2+42y=\sqrt[2]{x^{-2}+4}


y=1x2+42y=\sqrt[2]{\frac{1}{x^2}+4}


for real solutions of the term inside the square root should be as:

1x2+40\frac{1}{x^2}+4\ge0


We can se that has degree two so for all values of x the above term gives always positive values except x=0, as this makes it infinite value i.e. undefined, so the domain of the given equation is as:

Domain = (,+-\infty,+\infty )-[0] i.e the transformation will lie on x axis


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