Question #16538

Show that for any ring R, the center of the matrix ring Mn(R) consists of the diagonal matrices r • In, where r belongs to the center of R.
1

Expert's answer

2012-10-25T09:53:28-0400

Let EijE_{ij} be the matrix units. If rZ(R)r \in Z(R) , then (rIn)(aEij)=raEij=(aEij)(rIn)(r \cdot I_n)(aE_{ij}) = raE_{ij} = (aE_{ij})(rI_n) , so rInZ(S)r \cdot I_n \in Z(S) , where S=Mn(R)S = \mathbf{M}_n(R) . Conversely, consider M=rijEijZ(S)M = \sum r_{ij}E_{ij} \in Z(S) . From MEkk=EkkMME_{kk} = E_{kk}M , we see easily that MM is a diagonal matrix. This and MEkl=EklMME_{kl} = E_{kl}M together imply that rkk=rllr_{kk} = r_{ll} for all k,lk, l , so M=rInM = r \cdot I_n for some rRr \in R . Since this commutes with all aIn(aR)a \cdot I_n(a \in R) , we must have rZ(R)r \in Z(R) .

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