Answer to Question #16513 in Algebra for fazeela popow

Question

factorize 3p^2-2p-5

Answer 1

we find roots of the equation

3p^2-2p-5=0
D=4+4*3*5=4*16=64
p1,2=(2+-8)/6 so p1=-1, p2=5/3
so
3p^2-2p-5=3(p+1)(p-5/3)