( x 3 + 2 x 2 − 2 x − 1 ) ÷ ( x − 1 )
x2+3x+1‾x−1∣x3+2x2−2x−1x3−x2‾3x2−2x3x2−3x‾x−1x−1‾0Answer:x2+3x+1.\quad\quad\quad\quad\quad\quad\underline {\quad\quad \quad x^{2}+3x+1} \\ \quad\quad\quad \quad x-1| x^{3}+2x^{2}-2x-1\\ \quad\quad\quad\quad\quad\quad\quad\underline {x^3-x^2}\\ \quad\quad\quad\quad\quad\quad\quad\quad\quad3x^2-2x\\ \quad\quad\quad\quad\quad\quad\quad\quad\quad \underline{3x^2-3x}\\ \quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad x-1\\ \quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad \underline{x-1}\\ \quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad0\\ Answer: x^2+3x+1 .x2+3x+1x−1∣x3+2x2−2x−1x3−x23x2−2x3x2−3xx−1x−10Answer:x2+3x+1.
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