Determine the primary and reciprocal trig ratios for the following angles.
a) (7pi)/4
b) (- 2pi)/3
Primary:
sin(7π/4)=−(2/2)sin(7\pi/4) = -(\sqrt2/2)sin(7π/4)=−(2/2)
cos(7π/4)=2/2cos(7\pi/4) = \sqrt2/2cos(7π/4)=2/2
tan(7π/4)=−1tan(7\pi/4) = -1tan(7π/4)=−1
sin(−2π/3)=−(3/2)sin(-2\pi/3) = -(\sqrt3/2)sin(−2π/3)=−(3/2)
cos(−2π/3)=−(1/2)cos(-2\pi/3) = -(1/2)cos(−2π/3)=−(1/2)
tan(−2π/3)=3tan(-2\pi/3) = \sqrt3tan(−2π/3)=3
Reciprocal:
sec(7π/4)=2sec(7\pi/4) = \sqrt2sec(7π/4)=2
csc(7π/4)=−2csc(7\pi/4) = -\sqrt2csc(7π/4)=−2
cot(7π/4)=−1cot(7\pi/4) = -1cot(7π/4)=−1
sec(−2π/3)=−2sec(-2\pi/3) = -2sec(−2π/3)=−2
csc(−2π/3)=−(2/3)csc(-2\pi/3) = -(2/\sqrt3)csc(−2π/3)=−(2/3)
cot(−2π/3)=3/3cot(-2\pi/3) = \sqrt3/3cot(−2π/3)=3/3
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