The first three terms of an arithmetic progression are 5x, 2x+3, and 2x+7 respectively. Find the value of x
"a_1=5x"
"a_1+d=2x+3"
"a_1+2d=2x+7"
Substituting for the value "a_1"
"5x+d=2x+3"
"5x+2d=2x+7"
Forming simultaneous equation and solving by substitution ;
"3x+d=3"
"3x+2d=7"
"d=3-3x"
"6-6x+3x=7"
"6-3x=7"
"3x=13"
"x=\\frac{13}{3}"
Comments
Leave a comment