Solve using the quadratic formula:
x2 + 4x + 3 = 0
For the quadratic equation
"ax^2+bc+c=0"
the formula for the roots is
"x=\\frac{-b\u00b1 \\sqrt{b^2-4ac}}{2a}"
For. "x^2+4x+3=0"
"a=1, b=4, c= 3"
Hence
"x=\\frac{-4\u00b1 \\sqrt{4^2-(4\u00d71\u00d73)}}{2\u00d71}"
"x=\\frac{-4\u00b1 \\sqrt{16-12}}{2}"
"x=\\frac{-4\u00b1 \\sqrt{4}}{2}"
"x=\\frac{-4\u00b12}{2}"
"x"1"=-1"
"x" 2"=-3"
Hence
"x" is either -1 or -3
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