Solve using the quadratic formula:
x2 + 4x + 3 = 0
For the quadratic equation
ax2+bc+c=0ax^2+bc+c=0ax2+bc+c=0
the formula for the roots is
x=−b±b2−4ac2ax=\frac{-b± \sqrt{b^2-4ac}}{2a}x=2a−b±b2−4ac
For. x2+4x+3=0x^2+4x+3=0x2+4x+3=0
a=1,b=4,c=3a=1, b=4, c= 3a=1,b=4,c=3
Hence
x=−4±42−(4×1×3)2×1x=\frac{-4± \sqrt{4^2-(4×1×3)}}{2×1}x=2×1−4±42−(4×1×3)
x=−4±16−122x=\frac{-4± \sqrt{16-12}}{2}x=2−4±16−12
x=−4±42x=\frac{-4± \sqrt{4}}{2}x=2−4±4
x=−4±22x=\frac{-4±2}{2}x=2−4±2
xxx1=−1=-1=−1
xxx 2=−3=-3=−3
xxx is either -1 or -3
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