Question #161571

Expand and simplify each function. Evaluate at f(-2). a. f(x) = (x + 1)(x - 2) (x + 3) b. f(x) = (2x ^ 2 - 3)(x ^ 3 + 1)


Expert's answer

(a). (x+1)(x−2)(x+3)\left(a\right).\:\left(x+1\right)\left(x-2\right)\left(x+3\right)

(x(x−2)+1(x−2)(x+3))\left(x\left(x-2\right)+1\left(x-2\right)\left(x+3\right)\right)

(x2−2x+x+2)(x+3)\left(x^2-2x+x+2\right)\left(x+3\right)

(x2−x+2)(x+3)\left(x^2-x+2\right)\left(x+3\right)

x3−x2+2x+3x2−3x+2 x^3-x^2+2x+3x^2-3x+2\:

x3+2x2−x+2x^3+2x^2-x+2

at f(−2)=−2:at\:f\left(-2\right)=-2:

=(−2)3+2(−2)2−(−2)+2 =\left(-2\right)^3+2\left(-2\right)^2-\left(-2\right)+2\:

=−8+8+2+2 =-8+8+2+2\:

=4=4


(b). (2x2−3)(x3+1)\left(b\right).\:\left(2x^2-3\right)\left(x^3+1\right)

2x2(x3+1)−3(x3+1)2x^2\left(x^3+1\right)-3\left(x^3+1\right)

2x5+2x2−3x3−32x^5+2x^2-3x^3-3

2x5+3x3+2x2−32x^5+3x^3+2x^2-3

at f(x)=−2at\:f\left(x\right)=-2

=2(−2)5+3(−2)3+2(−2)2−3=2\left(-2\right)^5+3\left(-2\right)^3+2\left(-2\right)^2-3

=−64−24+8−3=-64-24+8-3

=−83=-83



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