Question #160392

Given { t, f, 7r, 3n, 9n,...}:

(a) Find the 12th term.

(b) Find the sum of the first 12 terms.



1
Expert's answer
2021-02-03T03:56:59-0500

(a)

b4=3n,b5=9n,...b_4=3n, b_5=9n,...

q=3q=3


b12=3123n=19683nb_{12}=3^{12-3}n=19683n

The 12th term is 19683n.19683n.


(b)

b4+b5+...+b12=3n13913=29523nb_4+b_5+...+b_{12}=3n\cdot\dfrac{1-3^9}{1-3}=29523n

The sum of the first 12 terms is


S12=t+f+7r+29523nS_{12}=t+f+7r+29523n


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