1.Solve |3x+2|>=5. Show work and answer in interval notatation pls
2. Solve (2x-3)^2=-4
1
Expert's answer
2012-10-10T07:44:22-0400
1.Solve |3x+2|>=5. Show work and answer in interval notation
|3x+2|>=5& lt;==>
-5>=3x+2>=5& lt;==>
-7>=3x>=3& lt;==>
-7/3>=x>=1& lt;==>
xє(-∞;-7/3]U[1;+∞).
2.
Solve (2x-3)^2=-4 4x^2-12x+9=-4 4x^2-12x+9+4=0 4x^2-12x+13=0 D=144-52*4<0 => this equation has no real roots. However, we can find its complex roots: x1,1=(12+-sqrt(-64))/8=(12+-8i)/8 x1=3/2+i x2=3/2-i
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