Answer to Question #159609 in Algebra for Hasan

Question

In American football, the playing field is 53.33 yards (yd) wide by 120 yards (yd) long. For a special game, the field staff want to paint the playing field orange. Of course, they will use biodegradable paint available for purchase in 25-gallon (gal) containers. If the paint is applied in a thickness of 1.2 millimeters (mm) in a uniform layer, how many containers of paint will they need to purchase?

Answer 1

$Solution:~playing ~field ~dimensions~ \\w~=~53.33~ \\yd= 53.33*0.9144=48.76~m \\l=120~yd=109.728~m \\container's ~ volume=25~gallon=0.094625 ~m^3 \\applied~ paints ~thickness ~(t)=1.2~mm=0.0012~m \\so ~containers ~needed = \frac{playing~ field ~area ~X~ applied ~paint ~thickness}{volume ~of ~1 ~container} \\=\frac{48.76~X~109.728~X~0.0012}{0.094625}=\frac{6.42040}{0.094625} = 67.85 \approxeq 68 \\\therefore Nearly ~68 ~containers ~needed.$