Answer to Question #157781 in Algebra for Jonathan

Question

Solve for x to the nearest 10th.

63=1.08^x+20

Answer 1

$63=1.08^x+20$

$43 = 1.08^x$

$log_{1.08}43 = x$

$x = \large\frac{lg43}{lg1.08}$ = 48.871

to the nearest tenth is 48.9