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Answer to Question #157781 in Algebra for Jonathan

Question #157781

Solve for x to the nearest 10th.


63=1.08^x+20



1
Expert's answer
2021-01-26T04:10:04-0500

"63=1.08^x+20"

"43 = 1.08^x"

"log_{1.08}43 = x"

"x = \\large\\frac{lg43}{lg1.08}" = 48.871

to the nearest tenth is 48.9


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