t(x)=-x²+7x+1 and r(x)=5x²-2x+8,find (t-r)(2).
"t(x)=-x^2+7x+1" and "r(x)=5x^2-2x+8"
"(t-r)(x)=-x^2+7x+1-(5x^2-2x+8)=-x^2+7x+1-5x^2+2x-8=-6x^2+9x-7"
"(t-r)(2)=-6\\cdot 2^2+9\\cdot 2-7=-24+18-7=-13"
Answer: "(t-r)(2)=-13."
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