Solution:
area of space available,A=500m2area of space take by pen,AP=5003m2therefore,0≤Ap≤A⇒0≤5003≤500 {the required equation}area\,of\,space\,available, A = 500m^2 \\ area\,of\,space\,take\, by\,pen, A_P = \frac{500}{3}m^2 \\ therefore, \\ 0 \leq A_p \leq A \\ \Rightarrow 0 \leq \frac{500}{3} \leq 500 \,\,\,\,\,\,\,\, \{ the\, required\,equation \}areaofspaceavailable,A=500m2areaofspacetakebypen,AP=3500m2therefore,0≤Ap≤A⇒0≤3500≤500{therequiredequation}
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