To find an arithmetic sequence is to find a and d.
Its second, third and seventh terms are 2+d, 2+2d and 2+6d . Therefore
(2+2d)2 = (2+d)(2+6d)
⇒ 4+8d+4d2=4+14d+6d2
⇒ 2d2+6d=0
⇒ d=0,−3
For Second terms d = 0 , -3
Second term 2 + d
i) 2 + 0 = 2
ii) 2 + (-3) = 2-3 = -1
2 , -1 are the possible second terms
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