Answer to Question #148909 in Algebra for Nikhil Rawat

Question #148909
Find all the roots of 1+z^6=0, and show them in an argnad diagram
1
Expert's answer
2020-12-09T16:05:12-0500

Given that "1 +Z^6 = 0"


"Z^6 = -1\\\\\nZ = (-1)^{1\/6}\\\\\nZ = (-1+0*i)^{1\/6}\\\\\nZ_k = (cos\\pi+ i*sin(2*k*\\pi+\\pi))^{1\/6} \\\\\nk = 0,1,2,3,4,5\\\\\nZ_k = cos(2*k+1)*\\pi\/6"


  • if k = 0:

"Z_0 = cos \\pi\/6+isin\\pi\/6 = \\sqrt3\/2+i*1\/2"


  • if k = 1:

"Z_1 = cos (3*\\pi\/6)+i*sin(3*\\pi\/6)= cos\\pi\/2+i*sin\\pi\/2 = 0+i*1"


  • if k = 2:

"Z_2 = cos (5*\\pi\/6)+i*sin(5*\\pi\/6)= -\\sqrt3\/2+i*1\/2"


  • if k = 3:

"Z_3 = cos (7*\\pi\/6)+i*sin(7*\\pi\/6)= -\\sqrt3\/2+i*(-1\/2)"


  • if k = 4:

"Z_4 = cos (9*\\pi\/6)+i*sin(9*\\pi\/6)= cos(3*\\pi\/2)+ i*sin3*\\pi\/2=0+i*(-1)=0-i"

  • if k = 5:

"Z_5 = cos (11*\\pi\/6)+i*sin(11*\\pi\/6)= cos(360-30)+ i*sin(360-30 )=\\sqrt3\/2-i*1\/2"





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