"60 \\leqslant P \\leqslant150"
total revenue for selling "750-5P donuts\\, \\text{is} (750 -5P)P=750P-5P^{2}"
for maximum "\\frac{d}{dP}(750P-5P^{2})=0"
"750 - 10P=0"
"P= 750\/10 = 75"
The shop should charge "75 pence" per donut so that maximum revenue "=750\\times 75 - 5\\times 75^{2} = 28125 pence"
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