60⩽P⩽15060 \leqslant P \leqslant15060⩽P⩽150
total revenue for selling 750−5Pdonuts is(750−5P)P=750P−5P2750-5P donuts\, \text{is} (750 -5P)P=750P-5P^{2}750−5Pdonutsis(750−5P)P=750P−5P2
for maximum ddP(750P−5P2)=0\frac{d}{dP}(750P-5P^{2})=0dPd(750P−5P2)=0
750−10P=0750 - 10P=0750−10P=0
P=750/10=75P= 750/10 = 75P=750/10=75
The shop should charge 75pence75 pence75pence per donut so that maximum revenue =750×75−5×752=28125pence=750\times 75 - 5\times 75^{2} = 28125 pence=750×75−5×752=28125pence
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