Answer to Question #145765 in Algebra for liam donohue

Question #145765

Let h(t)=3t³/2−4t−3/2. Compute the following.

h′(t) =

h′(5) =

h′′(t) =

h′′(5) =

Expert's answer

h'(t)=9t²/2 -4

h'(5)=9x5²/2 -4=108.5

h''(t)=18t/2=9t

h''(5)= 9x5=45

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