"\\begin{aligned}\n\\left(\\frac{(4x^6)^3(4y^{-8})}{(2x)^4(12y^3)^2}\\right)^{\\frac{1}{2}} &= \\frac{(2x^3)^3(2y^{-4})}{(2x)^2(12y^3)}\n\\\\&=\\frac{16x^9 y^{-4}}{48x^3y^3} = \\frac{x^6}{3y^7}\n\\end{aligned}"
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment