Answer to Question #142940 in Algebra for xx

Question #142940

write in the form of x=g(x)
e^x+arcsin(x)=0

Expert's answer

"e^x + arcsin(x) =0\\\\\ne^x =-arcsin(x)\\\\\n-e^x=arcsin(x)\\\\\nsin(-e^x)=x\\\\\nx=sin(-e^x)\\\\\nx=-sin(e^x)\\\\\n\\textsf{This is in the form x=g(x)}\\\\\n\\textsf{Where } g(x)=-sin(e^x)"

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