Question

–4(3 – 5x)≥ –6x + 9

Answer 1

$–4(3 – 5x)≥ –6x + 9$

In order to solve this inequality, we observe the following steps.

Step I: Open the bracket

$-12+ 20x ≥ -6x +9$

Step II: Collect like terms

$20x +6x ≥ 9+12$ Simplifying this, we have;

$26x ≥ 21$ Divide both sides by $26,$ we have;

$\frac{26x}{26} ≥ \frac{21}{26}$ $26$ cancels out, hence;

$x ≥ \frac{21}{26}$

Therefore, the final answer is $x ≥ \frac{21}{26}$