Answer to Question #140352 in Algebra for Mikaella Llavor

Question

Mika has three and seven-sixteenths cm of wire.she needs only two and five-eigths cm of wire for her prodject in TLE how much wire does she need to cut??

Answer 1

Length of wire Mika has$= 3\frac{7}{16}cm = \frac{55}{16}cm$

Length of wire Mika needs $= 2\frac{5}{8}cm = \frac{21}{8}cm$

Length she has = Length she needs + Length she cuts

$\therefore$ Length she cuts = Length she has $-$ Length she needs

Length she cuts $=\frac{55}{16} - \frac{21}{8} = \frac{13}{16}cm$

$\therefore$ The length of wire she cuts is thirteen-sixteenths cm