"1. \\frac{13}{49} = \\frac{26}{7x}\\\\\n\\textsf{Dividing both sides by} \\frac{13}{7},\\\\\n\n\\frac{1}{7} = \\frac{2}{x}\\\\\nx = 14\\\\\n2. \\frac{b + 1}{b - 1} = \\frac{5}{6}\\\\\n\\textsf{Multiplying both sides by 6(b-1)},\\\\\n6b + 6 = 5b -5\\\\\n6b - 5b = -5-6\\\\\nb = -11\\\\\n3.\\frac{b-1}{b+1} = \\frac{5}{6}\\\\\n\\textsf{Multiplying both sides by 6(b+1)}\\\\\n6b-6 = 5b+5\\\\\n6b-5b = 5+6\\\\\nb=11"
Comments
Leave a comment