Question #138606

Adriano bought 9 soft and hard sweets in total. Soft sweets cost R3 each and hard sweets cost R2 each.If Adriano spent a total of R22, then how many soft sweets did he buy? 


Expert's answer

Let the number of soft sweets be ....ss and the hard sweets be..... hh

Hence

s+h=9s+h =9

s=9−hs=9-h and h=9−sh=9-s


And the cost of soft sweets will be (R3)ss and for hard sweets be (R2)hh


Hence

R(3s+2h)=R22R(3s + 2h) = R22

3s+2h=223s+2h=22

Replace value of h to be (9-s)

3s+2(9−s)=223s + 2(9-s)=22

3s+18−2s=223s+18-2s=22

3s−2s=22−183s-2s=22-18

s=4s=4

h=9−4=5h=9-4=5

Hence the number of soft sweets is 4

and number of hard sweets is 5




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