Answer to Question #137980 in Algebra for sir jhosee keyyt

Question

a cannonball is fired vertically upward from ground level with a speed of 160 feet and second the equation that give the cannonball high above the ground is h = 16t² + 160t where is the height is the height measured in feet tls in the time measured and the second how high its cannon but after 3 seconds

Answer 1

Use the equation for height:

$$h = -16t² + 160t,\\ h=-16\cdot3^2+160\cdot3=336\text{ feet}$$