Answer to Question #137595 in Algebra for Hoang Nguyen

Question

Hector raked 1 bag of leaves in 0.5 hours and 3 bags in
1.5 hours. Blaine raked 3 bags of leaves in 1 hour and
6 bags in 2 hours. Who raked leaves at a greater rate?

Answer 1

Hector

Total bags = 4bags

Total time taken = 2hours

Blaine

Total bags = 9bags

Total time taken = 3hours

Rate at which Hector raked:

= 4bags÷2hours = 2 bags per hour

Rate at which Blaine raked:

= 9bags÷3hours = 3 bags per hour

Since Blaine has a higher rate, that implies Blaine raked leaves at a greater rate.