Answer to Question #136573 in Algebra for Glayzel May

Question

aA computer analyst accepts a job at a starting salary of PHP 32186.00 and receives an increase of PHP 2500.00 annually for six years. What would be his salary in the fifth year? How much would he have received for the 5 - year period.

Answer 1

$a_n=a_1+(n-1)d$

n=5

a₅=5^th year salary

d=annual increase

a₁=starting salary

$a_1= 32186.00$

$d=2500.00$

$a_5=32186+(5-1)2500$

$a_5=42186$

5^th year salary=PHP 42186.00

$S_n=\cfrac{n}{2}(2a+(n-1)d)$

$S_5=\cfrac{5}{2}(2*32186+(5-1)2500)$

$S_5=185930$

Total salary for 5year period=PHP 185930.00