What is the sum or difference in 4/5 and 7/8
"\\frac{4}{5}+\\frac{7}{8}=\\frac{4\u20228+7\u20225}{5\u20228}=\\frac{32+35}{40}=\\frac{67}{40}"
"\\frac{4}{5}-\\frac{7}{8}=\\frac{4\u20228-7\u20225}{5\u20228}=\\frac{32-35}{40}=-\\frac{3}{40}".
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