we can use the model for continuous exponential decay
"m = m_0e^{kt}"
where m0 =0.8 initial mass
t = 60 time in days
k = -1.15/100 = -0.0115 continuous growth rate
e base of natural logarithm
m ending value mass
"m = m_0e^{kt} = 0.8*e^{-0.0115*60} = 0.8*e^{-0.69} \\approx 0.401"
Answer: 0.401g
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