Answer to Question #133905 in Algebra for Daniel

Question #133905

62

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√6


1
Expert's answer
2020-09-21T16:36:12-0400
"\\dfrac{6^2}{\\sqrt{6}}=\\dfrac{6^2}{\\sqrt{6}}\\cdot\\dfrac{\\sqrt{6}}{\\sqrt{6}}=\\dfrac{6^2}{6}\\sqrt{6}=6\\sqrt{6}"


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