By taking LCM of the given equation we get,
5−23−35=5∗1515−2∗53∗5−3∗35∗35- \frac {2}{3}- \frac{3}{5} = 5* \frac{15}{15}- \frac {2*5}{3*5}- \frac{3*3}{5*3}5−32−53=5∗1515−3∗52∗5−5∗33∗3
=7515−1015−915=\frac {75}{15}-\frac {10}{15}-\frac {9}{15}=1575−1510−159
=75−10−915=5615= \frac{75-10-9}{15}= \frac{56}{15}=1575−10−9=1556
Hence,
5−23−35=5615=3.733335- \frac {2}{3}- \frac{3}{5} = \frac{56}{15} = 3.733335−32−53=1556=3.73333
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