Answer to Question #130451 in Algebra for Everlyn

Question

Solve and check the linear equation. x+3/18=1/9+x-3/5

Answer 1

In the posted question the term 'x' in the equation gets cancelled on both the sides which makes it unsolvable.

So let us consider the same equation with a small correction and solving the same as under :

(x + 3)/18 = 1/9 + (x - 3)/5

Multiplying both sides by 90 we get,

$90*\frac {(x + 3)}{18} = 90*\frac {1}{9} + 90*\frac{(x - 3)}{5}$

Hence,

5(x + 3) = 10 + 18(x - 3)

5x + 15 = 10 + 18x - 54

13x = 59

x = 59/13

So now substituting the value of x in the given equation we get,

LHS = (x + 3)/18 = (59/13 + 3)/18 = 49/117

RHS = 1/9 + (x - 3)/5 = 49/117

Since, LHS = RHS the calculated value of x = 59/13 is correct.