Answer to Question #129991 in Algebra for Sphesihle Zuma

Question

A man had 243 golden coins and he shared them equally among his three children. His three children then each shared the coins equally among their three children. It went on like this until the last generation had one coin each.
1 person:241coins
3 people :81coins
9 people:27 coins
27 people :9 coins
81 people :3 coins
A, write down the number sequence that represents this situation.
B, set up a table to represent the situation above.
C, describe in words how this geometric sequence has developed.
D, use a table to sketch a graph

Answer 1

( A ) . NUMBER SEQUENCE :

243 , 81 , 27 , 9 , 3 , 1

( B ) .

( C ) . The problem states a man having originally 243 golden coin . this amount is shared to three of his children equally . We then divide 243 by 3 - giving each child 81 coins each . Now , these 81 coins are also shared equally among their own three children 27 coins each . This pattern goes on until the last set of three children have 1 coin each . The number sequence then suggests to divide the previous number by three to get the number for the next sequence.

( D ) .