Question #128754

Solve quadratic equation x2 - x - 1 = 0


Expert's answer

Solution


The problem can be solved using quadratic formula which state: x = −b±b2−4ac2a\frac{-b\pm\sqrt{b^2-4ac}}{2a}

the formula is for equations such as ax2+bx+c=0ax^2+ bx + c = 0

where in this problem x2−x−1= 0 

a=1, b=-1, c=-1

substituting a,b,and c in the quadratic formula we get;

x =−(−1)±  (−1)2−4(1)(−1)2×1\frac{-(-1)\pm\ \ \sqrt{(-1)2-4(1)(-1)}}{2\times1}

this gives out

x = 1±  1 + 42\frac{1\pm\ \ \sqrt{1\ +\ 4}}{2}

therefore x =1−  52or1 +  52\frac{1-\ \ \sqrt5}{2} or \frac{1\ +\ \ \sqrt5}{2}

Hence x=−0.62 or x=1.62


Answer.

x=−0.62 or x=1.62



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