Question #126036

Find the general term Tn for the following sequences;
a) 9; 14; 19
b) 3; 7; 11
c) 8; 15; 22
d) 4; 11; 18

Expert's answer

a)9;14;19a) 9; 14; 19

a1=9;a2=14;a3=19  ⟹  a_1=9;a_2=14;a_3=19\implies a2−a1=14−9=5a_2-a_1=14-9=5

=a3−a2=19−14=5  ⟹  d=5=a_3-a_2=19-14=5\implies d=5 (Common Difference)

So,This is an A.P.A.P.

Tn=a1+(n−1)d=9+(n−1)5=4+5nT_n=a_1+(n-1)d=9+(n-1)5=4+5n

b) 3;7;11b) \ 3; 7; 11

a1=3;a2=7;a3=11  ⟹  a_1=3;a_2=7;a_3=11\implies a2−a1=7−3=4a_2-a_1=7-3=4

=a3−a2=11−7=4  ⟹  d=4=a_3-a_2=11-7=4\implies d=4

So,This is an Arithmetic progression.

Tn=a1+(n−1)d=3+(n−1)4=−1+4nT_n=a_1+(n-1)d=3+(n-1)4=-1+4n

c) 8;15;22c)\ 8; 15; 22

a1=8;a2=15;a3=22  ⟹  a_1=8;a_2=15;a_3=22\implies a2−a1=15−8=7a_2-a_1=15-8=7

=a3−a2=22−15=7  ⟹  d=7=a_3-a_2=22-15=7\implies d=7

So,This is an Arithmetic progression.

Tn=a1+(n−1)d=8+(n−1)7=1+7nT_n=a_1+(n-1)d=8+(n-1)7=1+7n

d) 4;11;18d) \ 4; 11; 18

a1=4;a2=11;a3=18  ⟹  a_1=4;a_2=11;a_3=18\implies a2−a1=11−4=7a_2-a_1=11-4=7

=a3−a2=18−11=7  ⟹  d=7=a_3-a_2=18-11=7\implies d=7

So,This is an Arithmetic progression.

Tn=a1+(n−1)d=4+(n−1)7=−3+7nT_n=a_1+(n-1)d=4+(n-1)7=-3+7n


LATEST TUTORIALS
APPROVED BY CLIENTS