Answer to Question #125945 in Algebra for Preeti Sarkar

Question

The product of two even integers is 2020.Find their sum.

Answer 1

Solution:

2n⋅2m=2020 (n, m in Z₊).

n⋅m=505 ⟹ m=505/n⟹ n=1 or n=5 or n=101 or n=505.

n₁=1,m₁=505; n₂=5,m₂=101; n₃=101,m₃=5; n₄=505,m₄=1⟹ 

sum₁=2n₁+2m₁=1012,

sum₂=2n₂+2m₂₌212,

sum₃=2n₃+2m₃=212,

sum₄=2n₄+2m₄=1012.

Answer: sum=1012 or sum=212