Let an be the n -th element of the sequence: 0,3,8,15,…
Then an=n2−1
a1=12−1=0
a2=22−1=3
a3=32−1=8
a4=42−1=15
1.The next term is a5=52−1=24 ,
1.1 The eleventh term of this sequence is a11=112−1=121−1=120 , a11=120
1.2 an+1−an=((n+1)2−1)−(n2−1)=n2+2n+1−1−n2+1=2n+1
Type of numbers: odd numbers.
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