Question

Simplify X^p+(1/2)q × Y^2p-q ÷ (XY^2)^p × √X^q

Answer 1

$\dfrac{x^{p+\frac{1}{2}q} \cdot y^{(2p-q)}}{(x\cdot y^2)^p \cdot \sqrt{x}^q} = \dfrac{x^p\cdot x^{\frac{1}{2}q} \cdot y^{2p}\cdot y^{-q}}{x^p\cdot y^{2p} \cdot x^{\frac{1}{2}q}} = y^{-q}$