Question

A curve has equation f(x)=2x^2/x^2−1. What are the x and y intercepts if they exist.

Answer 1

The y-intercept, $x=0$

$f(x)$ $=$ $2x^2\over {x^2-1}$

$=$ $2(0)^2\over 0^2-1$

$=0$

$(0,0)$

The y-intercept $y=0$

$0=$ $2x^2\over x^2-1$

$0(x^2-1)=2x^2$

$0=2x^2$

$=(0,0)$

The x and y intercept are both