Solution.
Let it is added x gram of 100% alcohol. Find the weight of alcohol, which must be added:
x∗1+480∗0.24=(x+480)∗0.4;x+115.2=0.4x+192;0.6∗x=76.8;x=128.x*1+480*0.24=(x+480)*0.4;\\ x+115.2=0.4x+192;\\ 0.6*x=76.8;\\ x=128.\\x∗1+480∗0.24=(x+480)∗0.4;x+115.2=0.4x+192;0.6∗x=76.8;x=128.
Answer: 128 gram.
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